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Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po) ?

By   July 21, 2022

Question : Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po) ?

(a) H2S < H2O < H2Se < H2Te < H2Po
(b) H2O < H2S < H2Se < H2Te < H2Po
(c) H2Po < H2Te < H2Se < H2S < H2O
(d) H2Se < H2Te < H2Po < H2O < H2S
Answer : from all above options the correct answer is “(c) H2Po < H2Te < H2Se < H2S < H2O” and the reason behind it , On moving down the group the thermal stability for H2E decreases due to decrease in bond energy of H-E. Hence the correct order of stability is H2Po < H2Te < H2Se < H2S < H2O. and that is why we have marked option (c) for correct answer.
explanation of answer :
when we look at the table the order of O , S , Se , Te and Po is given as below –
as we know that on going up to down in table thermal stability for H2E decreases because going up to down the decrease in bond energy of H-E that is why the stability order will be as follows –
(c) H2Po < H2Te < H2Se < H2S < H2O