A bag contains slips numbered from 1 to 100. If Fatima chooses a slip at random from the bag, it will either be an odd number or an even number. Since, this situation has only two possible
question : A bag contains slips numbered from 1 to 100. If Fatima chooses a slip at random from the bag, it will either be an odd number or an even number. Since, this situation has only two possible outcomes, so the probability of each is 
Justify.
correct answer : probability of each is
explanation of correct answer :
Total number of slips = 100
so we can say total number of outcomes = 100
odd numbers from 1 to 100 = 1, 3, 5, 7, 9 , 11 , …97, 99
So total numbers of odd numbers from 1 to 100 are = 50
so probability of getting odd number = odd numbers/total numbers
probability of getting odd number = 50/100 = 1/2
so the probability of getting odd number = 1/2
even numbers from 1 to 100 are = 2, 4, 6, 8, 10 , 12…,96, 98, 100
so total total even numbers from 1 to 100 are = 50
so probability of getting even number = even numbers/total numbers
probability of getting even number = 50/100
probability of getting even number = 1/2
So we have seen that the probability of getting odd and even numbers is 1/2 in both (each) condition.
Hence proved.
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English medium Notes
Class 6
Hindi social science science maths English
Class 7
Hindi social science science maths English
Class 8
Hindi social science science maths English
Class 9
Hindi social science science Maths English
Class 10
Hindi Social science science Maths English
Class 11
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chemistry business studies biology accountancy
Class 12
Hindi physics physical education maths entrepreneurship english economics